Dengan menggunakan data berikut,
· Hitung nilai r
· Hitung nilai
₁

· Lakukan uji t untuk membuktikan H₀:
₁=0

· Lakukan uji t untuk membuktikan H₀:r = 0
Mg Serum
|
Mg Tulang
|
3.6
|
672.0
|
2.7
|
567.0
|
2.45
|
612.0
|
1.45
|
400.0
|
0.9
|
236.0
|
1.4
|
270.0
|
2.8
|
340.0
|
2.8
|
621.0
|
2.55
|
638.0
|
1.8
|
524.0
|
1.4
|
294.0
|
2.9
|
330.0
|
1.8
|
240.0
|
1.5
|
190.0
|
2.85
|
610.0
|
2.6
|
570.0
|
2.25
|
552.0
|
1.35
|
277.0
|
1.6
|
268.0
|
1.65
|
270.0
|
1.35
|
215.0
|
Model Summary
| ||||
Model
|
R
|
R Square
|
Adjusted R Square
|
Std. Error of the Estimate
|
1
|
.766a
|
.587
|
.566
|
111.894
|
a. Predictors: (Constant), Serum
|
Coefficientsa
| ||||||
Model
|
Unstandardized Coefficients
|
Standardized Coefficients
|
t
|
Sig.
| ||
B
|
Std. Error
|
Beta
| ||||
1
|
(Constant)
|
37.550
|
76.410
|
.491
|
.629
| |
Serum
|
180.948
|
34.793
|
.766
|
5.201
|
.000
| |
a. Dependent Variable: Tulang
|
a. Nilai r = 0.766
b. Nilai
₁ = 180.948

c. H₀ :
₁ = 0

t = 180.948 / 34.793
d. H₀:
= 0

t = 0.766
/
-0.766² = 3.338 / 0.643 = 5.191


Tabel t dengan n = 19 hasilnya 1.729
thitung 5.191 > ttabel 1.729
Maka dapat disimpulkan bahwa Mg Serum dan Mg tulang berkolerasi positif dan bermakna
LATIHAN 3
BB
|
GLUKOSA
|
64.0
|
108.0
|
75.3
|
109.0
|
73.0
|
104.0
|
82.1
|
102.0
|
76.2
|
105.0
|
95.7
|
121.0
|
59.4
|
79.0
|
93.4
|
107.0
|
82.1
|
101.0
|
78.9
|
85.0
|
76.7
|
99.0
|
82.1
|
100.0
|
83.9
|
108.0
|
73.0
|
104.0
|
64.4
|
102.0
|
77.6
|
87.0
|
Model Summary
| ||||
Model
|
R
|
R Square
|
Adjusted R Square
|
Std. Error of the Estimate
|
1
|
.484a
|
.234
|
.180
|
9.276
|
a. Predictors: (Constant), BB
|
Coefficientsa
| ||||||
Model
|
Unstandardized Coefficients
|
Standardized Coefficients
|
t
|
Sig.
| ||
B
|
Std. Error
|
Beta
| ||||
1
|
(Constant)
|
61.877
|
19.189
|
3.225
|
.006
| |
BB
|
.510
|
.246
|
.484
|
2.070
|
.057
| |
a. Dependent Variable: GLUKOSA
|
a. Hitung nilai r
r = 0.234
b. Hitung nilai
₁


c. Lakukan uji t untuk membuktikan H₀ :
₁ = 0

t = 0.510 / 0.246
d. Lakukan uji t untuk membuktikan H₀:r = 0
t = (0.234 x 3.741) / 0.972 = 0.900
Tabel t dengan n=14 hasilnya 1.761
thitung 0.9 < ttable 1.761
Maka dapat disimpulkan bahwa BB dan Kadar Glukosa tidak memiliki korelasi dan tidak bermakna.
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